Unfortunately, the desired output should actually be the negative of our original choice for VO in Fig. 1. Thus, a sign error also appears in Eqs. (13) and (14) and of the text. The desired outputs are:
VVDP0°VVDP90°=VVDP[3.16π44(σ11σ22)]
(13)
VVDP+45°VVDP45°=VVDP[3.16(2πD)σ12]
(14)